Help to find mistake lim_{x ->0 } (tan x - sin x)/(sin^3x)

Kayleigh Dixon

Kayleigh Dixon

Answered question

2022-01-28

Help to find mistake
PSKlimx0tanx-sinxsin3x=[1-10]=[00]=limx0tanxxx-sinxxxsin3x=limx0x(tanxx-sinxx)sin3xZSK
What to do with the denominator. Also the numerator in its current state converges to:
[0(1-1)]=[0]
which is problematic since correct solution is 12

Answer & Explanation

trasahed

trasahed

Beginner2022-01-29Added 14 answers

From Taylor expansion,
limx0tanxsinxsin3x=limx0x+13x3(xx33!)+o(x3)x3+o(x3)
=limx0(13+16)x3x3
=13+16
=12
Flickkorbma

Flickkorbma

Beginner2022-01-30Added 17 answers

limx0x(tanxxsinxx)sin3x
is of the form
00
which is Indeterminate .
Try
As x0sinx0sinx0
tanxsinxsin3x=1cosxcosxsin2x
Again,
1cosxsin2x=1cosx(1cosx)(1+cosx)=11+cosx
for 1cosx0cosx1 which is true as x0

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