Find \lim_{n\to\infty} \cos(\frac{\pi}{4}) \cos(\frac{\pi}{8})\ldots \cos(\frac{\pi}{2^n})

Abbie Mcgrath

Abbie Mcgrath

Answered question

2022-01-26

Find limncos(π4)cos(π8)cos(π2n)

Answer & Explanation

stamptsk

stamptsk

Beginner2022-01-27Added 23 answers

If xn=cos(π4)cos(π8)cos(π2n)
xnsin(π2n)=cos(π4)cos(π8)cos(π2n)sin(π2n)
=121cos(π4)cos(π8)cos(π2n1)sin(π2n1)
==12n1
So
xn=12n1sin(π2n)
So limnxn=2π

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