How do I show that \cos^4 x=\frac{1}{8}\cos(4x)+\frac{1}{2}\cos(2x )+\frac{3}{8} I know ho

Alex Cervantes

Alex Cervantes

Answered question

2022-01-28

How do I show that cos4x=18cos(4x)+12cos(2x)+38
I know how to prove that
cos2x=12+12cos(2x)
by substituting cos2x with 2cos2x1 according to the double angle identity
cos(2x)=2cos2x1
However, how do I do that for cos4x?
Do I do it by writing cos4x as
cos2(x)cos2(x)
and thus get it by squaring the LHS of
cos2x=12+12cos(2x)
Im not sure how to proceed.

Answer & Explanation

plusmarcacw

plusmarcacw

Beginner2022-01-29Added 10 answers

Hint: By squaring we get
cos4(x)=14(cos2(2x)+2cos(2x)+1)
and then
cos(4x)=2cos2(2x)1
Mazzuranavf

Mazzuranavf

Beginner2022-01-30Added 10 answers

Since
cos2x=12+12cos(2x)
we have
cos2(2x)=12+12cos(4x)
and thus, if we square first equation we get
cos4x=14+12cos(2x)+14cos2(2x)=
=14+12cos(2x)+14(12+12cos(4x))
=38+12cos(2x)+18cos(4x)

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