Range of f(x)= \frac{\tan{x}}{\tan{3x}} My Attempt: I wrote down, \tan{3x}=\frac{3\tan{x}-\tan^3{x}}{1-3\tan^2{x}} This reduced f(x) to, f(x)=\frac{1-3\tan^2{x}}{3-\tan^2{x}} I

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$$\left[\begin{array}{cccc}1& 3& 0& -4\\ 2& 6& 0& -8\end{array}\right]$$

Find, correct to the nearest degree, the three angles of the triangle with the given vertices
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Whether f is a function from Z to R if 
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b) ${\displaystyle f\left(n\right)=\sqrt{n^2+1}}$. 
c) ${\displaystyle f\left(n\right)=\frac{1}{n^2-4}}$.

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