How do you simplify 4(\cos(\frac{\pi}{3})+i\sin(\frac{\pi}{3}))\cdot 7(\cos(\frac{2\pi}{3})+i\sin(\frac{2\pi}{3})) and express the result

Madilyn Fitzgerald

Madilyn Fitzgerald

Answered question

2022-01-30

How do you simplify 4(cos(π3)+isin(π3))7(cos(2π3)+isin(2π3)) and express the result in rectangular form?

Answer & Explanation

coolbananas03ok

coolbananas03ok

Beginner2022-01-31Added 20 answers

Step 1
eiθ=cosθ+isinθ
Therefore, (cosα+isinα)(cosβ+isinβ)=eiαeiβ
=ei(α+β)
=cos(α+β)+isin(α+β)
Step 2
So in our example:
4(cos(π3)+isin(π3)7(cos(2π3)+isin(2π3))
=28(cos(π3+2π3)+isin(π3+2π3))
=28(cos(π)+isin(π))
=28(1+i0)
=28.

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