2022-03-06

( 2x+3y =103x+4y=20

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Skilled2022-03-14Added 403 answers

Given system of equation:$\{\begin{array}{l}2x+3y=10\\ 3x+4y=20\end{array}$ Write the problem as a mathematical expression.$2x+3y=10\phantom{\rule{0ex}{0ex}}3x+4y=20$ Solver for $x$ in 2x+3y =10$x=5-\frac{3y}{2}\phantom{\rule{0ex}{0ex}}3x+4y=20$ Replace all occurrences of $x$ with $5-\frac{3y}{2}$ in each equation.$15-\frac{y}{2}=20\phantom{\rule{0ex}{0ex}}x=5-\frac{3y}{2}$ Solve for $y$ in $15-\frac{y}{2}=20$ $y=-10\phantom{\rule{0ex}{0ex}}x=5-\frac{3y}{2}$ Replace all occurrences of $y$ with $-10$ in each equation.$x=20\phantom{\rule{0ex}{0ex}}y=-10$ The solution to the system is the complete set of ordered pairs that are valid solutions.$20,-10$ The result can be shown in multiple forms.Point Form: $20,-10$ Equation Form: $x=20,y=-10$

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