Given \sec^4\theta=\frac{16}{9} or \sec^4=\frac{(4)^2}{(3)^2} \Rightarrow\sec^2\theta=\frac{4}{3}\Rightarrow\theta=\sec^{-1}(\sqrt{\frac{4}{3}}) hence, \theta=2n\pi\pm\frac{\pi}{6}

Jasper Carlson

Jasper Carlson

Answered question

2022-02-28

Given sec4θ=169 or sec4=(4)2(3)2
sec2θ=43θ=sec1(43)
hence, θ=2nπ±π6

Answer & Explanation

Alexandra Haynes

Alexandra Haynes

Beginner2022-03-01Added 10 answers

9sec4θ=16
sec4θ=169
secθ=±23
cosθ=±32
θ=nπ±π6=(6n±1)π6,
where nZ

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?