Prove that \tan^{-1}(\frac{x+1}{1-x})=\frac{\pi}{4}+\tan^{-1}(x)

simnelsbl4

simnelsbl4

Answered question

2022-02-27

Prove that
tan1(x+11x)=π4+tan1(x)

Answer & Explanation

meizhen85ulg

meizhen85ulg

Beginner2022-02-28Added 6 answers

The identity should read
tan1(x+11x)=tan1(x)+π4
Let tan1(x)=θ i.e x=tan(θ). Then we get that
x+11x=tan(θ)+11tan(θ)
Recall that tan(A+B)=tan(A)+tan(B)1tan(A)tan(B)
Taking B=π4, we get that tan(A+π4)=tan(A)+11tan(A)
Hence, we get that
x+11x=tan(θ)+11tan(θ)=tan(θ+π4)
Hence,
tan1(x+11x)=θ+π4=tan1(x)+π4
Proof of tan(A+B)=tan(A)+tan(B)1tan(A)tan(B)
tan(A+B)=sin(A+B)cos(A+B)
=sin(A)cos(B)+cos(A)sin(B)cos(A)cos(B)sin(A)sin(B)
Assuming cos(A)cos(B)0, divide numerator and denominator by cos(A)cos(B), to get that

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