Does the equation a\cdot\cos(\theta)-b\cdot\sin(\theta)=c have a closed-form solution for \theta?

Abiha Bellamy

Abiha Bellamy

Answered question

2022-02-28

Does the equation
acos(θ)bsin(θ)=c
have a closed-form solution for θ?

Answer & Explanation

copausc20

copausc20

Beginner2022-03-01Added 8 answers

Using the identity sin(x)2+cos(x)2=1, we have,
acos(θ)bsin(θ)=ca1sin2(θ)=bsin(θ)+c
a2(1sin2(θ))=(bsin(θ)+c)2
(a2+b2)sin(θ)2+2bcsin(θ)+(c2a2)=0
The above equation is quadratic in sin(θ). Solving the equation in sin(θ) yields,
sin(θ)=2bc±4b2c24(a2+b2)(c2a2)2(a2+b2)

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