Find the limit \lim_{x\to1}\frac{(x^2-1)\sin(3x-3)}{\cos(x^3-1)\tan^2(x^2-x)}

haciendodedorcp

haciendodedorcp

Answered question

2022-03-01

Find the limit
limx1(x21)sin(3x3)cos(x31)tan2(x2x)

Answer & Explanation

Andrew Fenton

Andrew Fenton

Beginner2022-03-02Added 6 answers

sin(3x3)tan2(x2x)=sin(3x3)3x3×(x2xtan(x2x))2×3(x1)x2(x1)2
Hence
(x21)sin(3x3)cos(x31)tan2(x2x)=sin(3x3)3x3×(x2xtan(x2x))2×3(x1)(x21)x2(x1)2cos(x31)
=sin(3x3)3x3×(x2xtan(x2x))2×3(x+1)x2cos(x31)
Now the first and second term on the right has limit 1 as x1. The last term limit can be obtained by plugging x=1, to give the limit as
1×1×3×(1+1)12×cos(0)=6

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