How to integrate? \int\frac{\arctan\sqrt{x^2-1}}{\sqrt{x^2+x}}dx

Reginald Owens

Reginald Owens

Answered question

2022-03-01

How to integrate?
arctanx21x2+xdx

Answer & Explanation

e4mot1ic5bf

e4mot1ic5bf

Beginner2022-03-02Added 6 answers

Consider the integral
arccosxxx+1dx
which was derived by Mike. Using the property arccosx=π2arcsinx, we have
=π2dxxx+1arcsinxxx+1dx
The leftmost integral is evaluated trivially and so we consider the rightmost integral. We express 1x+1 in terms of its MacLaurin series, valid for |x|<1
arcsinxxk=0(12k)xkdx
=k=0(12k)xk1arcsinxdx
Then, upon consideration of the integral
xk1arcsinxdx
and an application of integration by parts, we find that
xk1arcsinxdx=xkkarcsinx1kxkdx1x2
According to Mathematica, the remaining integral may be expressed in terms of the hypergeometric function. This procedure may or may not provide an evaluation for |x|<1.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?