How does one get the following equalities ? 1+\tan x=\frac{\sin(\frac{\pi}{4}+x)}{\cos\frac{\pi}{4}\cos x}=\sqrt{2}\frac{\cos(\frac{\pi}{4}-x)}{\cos

iristh3virusoo2

iristh3virusoo2

Answered question

2022-02-28

How does one get the following equalities ?
1+tanx=sin(π4+x)cosπ4cosx=2cos(π4x)cosx

Answer & Explanation

Zernerqcw

Zernerqcw

Beginner2022-03-01Added 11 answers

1+tanx=1+sinxcosx=cosx+sinxcosx1212
=cosxsinπ4+sinxcosπ4cosπ4cosx=sin(x+π4cosπ4cosx
Using the fact that cosπ4=sinπ4=12

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