Why is this silution to 2\sin^2x(x)+\sin(x)-1=0 incorrect?

Jordana Boyd

Jordana Boyd

Answered question

2022-03-01

Why is this silution to 2sin2x(x)+sin(x)1=0 incorrect?

Answer & Explanation

aceptanteppt

aceptanteppt

Beginner2022-03-02Added 5 answers

Recall that
sin(A)=sin(B)A=nπ+(1)nB
Also, you could solve your problem in a slightly easier way. Note that
2sin2(x)+sin(x)1=(2sin(x)1)(sin(x)+1)=0
sin(x)=12 or -1
Hence,
x=nπ+(1)nπ6, 2nππ2

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