2nd solution of \cos x \cos 2x\cos 3x= \frac{1}{4} Attempt explained: (2\cos

Akbar Witt

Akbar Witt

Answered question

2022-03-01

2nd solution of cosxcos2xcos3x=14
Attempt explained:
(2cosxcos3x)cos2x=12
(cos4x+cos2x)cos2x=12 Let ,y=2x
cos2y+cosy(2cos2y1)=12

Answer & Explanation

Mikayla Swan

Mikayla Swan

Beginner2022-03-02Added 9 answers

It's
cos2x(cos2x+cos4x)=12
Now, let cos2x=t
Thus,
t(t+2t21)=12
or
4t3+2t22t1=0
or
2t2(2t+1)(2t+1)=0
or
(2t21)(2t+1)=0
which gives
cos4x=0
or
cos2x=12
and we can write the answer.

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