A particle executes SHM of amplitude 25cm and time period

Corbin Walton

Corbin Walton

Answered question

2022-03-02

A particle executes SHM of amplitude 25cm and time period 3s. What is minimum time required for the particle to move between two points 12.5cm on either side of mean position?

Answer & Explanation

Ian Adams

Ian Adams

Skilled2022-03-11Added 163 answers

Step 1Let A be the amplitude of SHM motion, T0 be the time period.Let t be the time taken for the particle to move between mean position to a position x.Write the expression for the motion of particle in SHM.x=Asin(ωt)=Asin(2πT0t)Step 2Substitute the known values in the above expression to get the time required for the particle to move to position x from the mean position.(12.5cm)=(25cm)sin(2π(3s)t)sin(2π(3s)t)=12.5cm25cm=12=sin(30)=sin(π6))2π(3s)t=π6t=14tStep 3Write the expression for the total time taken by the particle to move between position x between both side of the mean position.tto total=2t=2(14s)=12s=0.5s

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