Why is \(\displaystyle{\frac{{{0.5}}}{{{{\cos}^{{2}}{\left({30}\right)}}}}}={\frac{{{\tan{{\left({30}\right)}}}}}{{{\cos{{\left({30}\right)}}}}}}\), but \(\displaystyle{\frac{{{0.5}}}{{{{\cos}^{{2}}{\left({13}\right)}}}}}\ne{\frac{{{\tan{{\left({13}\right)}}}}}{{{\cos{{\left({13}\right)}}}}}}\)?

Thaddeus Nolan

Thaddeus Nolan

Answered question

2022-03-11

Why is 0.5cos2(30)=tan(30)cos(30), but 0.5cos2(13)tan(13)cos(13)?

Answer & Explanation

Jarrett Chan

Jarrett Chan

Beginner2022-03-12Added 6 answers

It's simply because sin(30)=12
Etallemms

Etallemms

Beginner2022-03-13Added 3 answers

If we use x as a variable, we get the following:
0.5cos2x=tanxcosx
12cosx=cos2xtanx
cosxtanx =12
cosxsinxcosx=12
sinx =12
Thus the only solutions to the above equation are x=30±360k or x=150±360k where k is any natural number.

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