What is the period for the following: \(\displaystyle{y}={10}{\sin{{\left({\frac{{{2}\pi}}{{{365}}}}{\left({x}-{50}\right)}\right)}}}\) Is

Joey Rodgers

Joey Rodgers

Answered question

2022-03-15

What is the period for the following:
y=10sin(2π365(x50))
Is the period
2π2π365
which would be 365 ?

Answer & Explanation

IdodaHekbed7mx

IdodaHekbed7mx

Beginner2022-03-16Added 4 answers

In general, divide the period of any function f(x) by the coefficient of x i.e. if T is the period of any function say f(x) then the period of function f(αx+β) is
=Tα
Hence, for the given function: y=10sin(2π365(x50))=10sin(2π365x200π365) Hence the period of given function
=period of  sinxcoefficient of  x=2π2π365=365

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