Alternative proof of \(\displaystyle{{\cos}^{{6}}\theta}+{{\sin}^{{6}}\theta}={\frac{{{1}}}{{8}}}{\lbrace}{\left({5}+{3}{\cos{{4}}}\theta\right)}\)

Charity Barr

Charity Barr

Answered question

2022-03-17

Alternative proof of
cos6θ+sin6θ=18{(5+3cos4θ)

Answer & Explanation

Karley Ayala

Karley Ayala

Beginner2022-03-18Added 1 answers

If so, you can use the Euler's identity to boil this down to a simple polynomial expression.
cosθ=12(eiθ+eiθ)
sinθ=12i(eiθeiθ)
Let's just say z=eiθ to shorten the notation. You have
126(z+1z)6126(z1z)6
=126((z6+6z4+15z2+20+15z2+6z4+z6)(z66z4+15z220+15z26z4+z6))
=164(40+2412(z4+z4))
=58+38cos4θ

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