Solve the equation \(\displaystyle{{\sin}^{{3}}{x}}+{{\sin}^{{3}}{\left({\frac{{{2}\pi}}{{{3}}}}+{x}\right)}}+{{\sin}^{{3}}{\left({\frac{{{4}\pi}}{{{3}}}}+{x}\right)}}+{\frac{{{3}}}{{{4}}}}{\cos{{2}}}{x}={0}\)

calcolare45pj

calcolare45pj

Answered question

2022-03-20

Solve the equation
sin3x+sin3(2π3+x)+sin3(4π3+x)+34cos2x=0

Answer & Explanation

Cason Harmon

Cason Harmon

Beginner2022-03-21Added 8 answers

Using the identity sin3θ=34sinθ14sin3θ, we get
sin3x+sin3(x+2π3)+sin3(x+4π3)
=34[sinx+sin(x+2π3+sin(x+4π3)]14[sin3x+sin(3x+2π)+sin(3x+4π)]
=340143sin3x
=34sin3x
Therefore, your equation is equivalant to 34sin3x+34cos2x=0

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