Solve the equation with trigonometry \(\displaystyle{\frac{{{2}{\cos{{x}}}}}{{{\left({1}+{\cos{{2}}}{x}\right)}}}}={\frac{{{\left({1}-{\cos{{2}}}{x}\right)}}}{{{\sin{{2}}}{x}}}}\)

Zack Mora

Zack Mora

Answered question

2022-03-20

Solve the equation with trigonometry
2cosx(1+cos2x)=(1cos2x)sin2x

Answer & Explanation

armejantm925

armejantm925

Beginner2022-03-21Added 20 answers

2cosx(1+cos2x)=(1cos2x)sin2x
2cosx(1+cos2(x)sin2(x))=(1(cos2(x)sin2(x)))(2sin(x)cos(x))
2cosx(2cos2(x))=(2sin2(x))2sin(x)cos(x)
1cos(x)=sin(x)cos(x)
1=sin(x)

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?