Solve the following question: \(\displaystyle{9}{\sin{{2}}}{x}-{40}{\cos{{2}}}{x}={\frac{{{41}}}{{\sqrt{{{2}}}}}}\)

Deegan Chase

Deegan Chase

Answered question

2022-03-22

Solve the following question:
9sin2x40cos2x=412

Answer & Explanation

umgebautv6v2

umgebautv6v2

Beginner2022-03-23Added 10 answers

Put 9=rcosy, 40=rsiny where y>0
Squaring and adding we get r2=1681=412r=41
cosy=9r=941, siny=4041
9cos2x40sin2y=412cos2xcosysin2xsiny
=12
cos(2x+arccos941)=12=cosπ4
2x+arccos941=2nπ±π4 where n is an integer

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