Solve this problem: \(\displaystyle\lim_{{{x}\to\frac{\pi}{{2}}}}{\frac{{{\cot{{x}}}}}{{{2}{x}-\pi}}}\)

tibukooinm

tibukooinm

Answered question

2022-03-22

Solve this problem:
limxπ2cotx2xπ

Answer & Explanation

Declan Cameron

Declan Cameron

Beginner2022-03-23Added 12 answers

Write cot(x) as cos(x)sin(x). We then have
limxπ2cot(x)2xπ=limxπ21sinxcos(x)2xπ
=limxπ21sin(x)limxπ2cos(x)2xπ
=1limπ2tπ2cos(π2t)2(π2t)π
=limt0sin(t)2t
=12limt0sin(t)t
=12

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