Limit of \(\displaystyle{x}^{{2}}{\left({1}-{x}{\sin{{\frac{{{1}}}{{{x}}}}}}\right)}\) as \(\displaystyle{x}\to\infty\)

justbethlflql

justbethlflql

Answered question

2022-03-23

Limit of x2(1xsin1x) as x

Answer & Explanation

Cody Hart

Cody Hart

Beginner2022-03-24Added 11 answers

It's
limx01sin{x}xx2=limx0xsin{x}x3=limx01cos{x}3x2=limx02sin2x234x24=16
Also, you can use
sin{x}=xx36+
and we obtain 16 immediately.

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