Would someone recommend a method of proving this

Makayla Stevens

Makayla Stevens

Answered question

2022-03-25

Would someone recommend a method of proving this relation?
|e2xsin(x)|x1+x2,x0
Unfortunately differentiation leads to messy transcendental expressions.

Answer & Explanation

Cason Harmon

Cason Harmon

Beginner2022-03-26Added 8 answers

|sinx|x, for x0 is well-known. On the other hand:
e2x=1+2x+(2x)22!+=1+2x+2x2+1+x2
therefore
e2x11+x2
taking products,
e2x|sinx|x1+x2

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