Given, \(\displaystyle{\cos{{\frac{{{x}}}{{{2}}}}}}+{\sin{{\left({3}{x}\right)}}}+\sqrt{{{3}}}{\left({\sin{{\frac{{{x}}}{{{2}}}}}}+{\cos{{\left({3}{x}\right)}}}\right)}\)

acidizihvzs

acidizihvzs

Answered question

2022-03-25

Given,
cosx2+sin(3x)+3(sinx2+cos(3x))

Answer & Explanation

pastuh7vka

pastuh7vka

Beginner2022-03-26Added 13 answers

cosx2+sin(3x)+3(sinx2+cos(3x))
=cosx2+3sinx2+sin(3x)+3cos(3x)
=2(12cosx2+32sinx2+12sin(3x)+32cos(3x))
Note that 12=sinπ6 and 32=cosπ6 so:
=2(sinπ6cosx2+cosπ6sinx2+sinπ6sin(3x)+cosπ6cos(3x))
Then using Addition Theorem:
=2(sin(x2+π6)+cos(3xπ6))
=2(sin(x2+π6)+sin(3x+π3))
Then using Sums to Products:
=4(sin(x2+π6+3x+π32)cos(x2+π63xπ32))
=4sin(7x+π4)cos(15xπ12)

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