Given: \(\displaystyle{\frac{{{1}-{\cos{{\left({x}\right)}}}+{k}{\sin{{\left({x}\right)}}}}}{{{\sin{{\left({x}\right)}}}+{k}+{k}{\cos{{\left({x}\right)}}}}}}\)

Kiara Haas

Kiara Haas

Answered question

2022-03-25

Given:
1cos(x)+ksin(x)sin(x)+k+kcos(x)

Answer & Explanation

Boehm98wy

Boehm98wy

Beginner2022-03-26Added 18 answers

1cosx+ksinxsinx+k(1+cosx)
=1cosx1cosx1cosx+ksinxsinx+k(1+cosx)
=(1cosx)(1cosx+ksinx)(1cosx)sinx+ksin2x
=(1cosx)(1cosx+ksinx)sinx(1cosx+ksinx)
=1cosxsinx

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