How can one simplify \(\displaystyle{\arctan{{\left({\frac{{{1}}}{{{\tan{\alpha}}}}}\right)}}}\)

Amya Horn

Amya Horn

Answered question

2022-03-25

How can one simplify
arctan(1tanα)

Answer & Explanation

anghoelv1lw

anghoelv1lw

Beginner2022-03-26Added 19 answers

When α=nπ then arctan1tanα is undefined. Therefore we may assume that
π2<β=(n+12)πα<π2
for a certain nZ. I claim that
arctan1tanα=β
whereby α=(n+12)π, i.e., tanα=±, corresponds to β=0 in a natural way.
Proof. One has π2<β<π2 by definition. When 0<β<π2 then π2β=αnπ, so that we obtain
tanβ=1tan(π2β)=1tanα
as required. Similarly one argues for π2<β<0

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?