development of \(\displaystyle\sum^{{{M}-{1}}}_{\left\lbrace{m}=-{\left({M}-{1}\right)}\right\rbrace}{e}^{{-{i}{m}{h}\xi}}\) \(\displaystyle\sum^{{{M}-{1}}}_{\left\lbrace{m}=-{\left({M}-{1}\right)}\right\rbrace}{e}^{{-{i}{m}{h}\xi}}={\frac{{{\sin{{\left({M}-{\frac}{12}\right)}}}{h}\xi}}{{{\sin{{\frac{{{1}}}{{{2}}}}}}{h}\xi}}}\) Can you show the

rhedynogh0rp

rhedynogh0rp

Answered question

2022-03-28

development of m=-(M-1)M-1e-imhξ
m=-(M-1)M-1e-imhξ=sin(M-12)hξsin12hξ
Can you show the process of the development?

Answer & Explanation

armejantm925

armejantm925

Beginner2022-03-29Added 20 answers

Set m=-r,
m=(M1)M1(ei2x)m=r=(M1)M1(ei2x)r
=e2ix(M1)d(e2ix)2M11ei2x1
=eixeix(eix)2M1(eix)2M1eixeix
Now eiyeiy=2isiny

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