prove that \(\displaystyle{\tan{{2}}}{x}={\frac{{{2}{\sin{{x}}}{\cos{{x}}}}}{{{1}-{2}{{\sin}^{{2}}{x}}}}}\)

blestimd4pz

blestimd4pz

Answered question

2022-03-29

prove that tan2x=2sinxcosx12sin2x

Answer & Explanation

Jared Kemp

Jared Kemp

Beginner2022-03-30Added 14 answers

2sinxcosx=sin2x, while 12sin2x=sin2x+cos2x2sin2x=cos2xsin2x=cos2x
Thus tan2x=sin2xcos2x

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