Prove that: \(\displaystyle{\frac{{{{\sin}^{{2}}{\left({2}\alpha\right)}}}}{{{{\sin}^{{2}}{\left(\alpha\right)}}}}}={4}-{4}{{\sin}^{{2}}{\left(\alpha\right)}}\)

limes14514qqmn

limes14514qqmn

Answered question

2022-03-29

Prove that:
sin2(2α)sin2(α)=44sin2(α)

Answer & Explanation

Denise Daniel

Denise Daniel

Beginner2022-03-30Added 8 answers

Using sinx=eixeix2i and cosx=eix+eix2, and sin2x+cos2x=1, write
sin22αsin2α=(sin2αsinα)2
=(e2iαe2iα2ieiαeiα2i)2
=((eiα+eiα)(eiαeiα)(eiαeiα))2=(eiα+eiα)2
=(2(eiα+eiα2))2
=4cos2α
=4(1sin2α)
=44sin2α

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