Prove that: \(\displaystyle{{\tan}^{{2}}{27}^{\circ}}+{2}{{\tan{{27}}}^{\circ}{{\tan{{36}}}^{\circ}=}}{1}\)

Jazmyn Holden

Jazmyn Holden

Answered question

2022-03-29

Prove that:
tan227+2tan27tan36=1

Answer & Explanation

Aidyn Wall

Aidyn Wall

Beginner2022-03-30Added 10 answers

The solution is nothing more than some computation and observing 227=9036.
tan2(27)+2tan(27)tan(36)=tan2(27)+2tan(27)cot(54)
=tan2(27)+2,tan(27)tan(54)
=tan2(27)+2,tan(27)2tan{27}1tan2(27)
=tan2(27)+2,tan(27)(1tan2(27))2tan{27}
=tan2(27)+(1tan2(27))
=1
where we have used the following identities:
tan(θ)=cot(90θ)
tan(2θ)=2tanθ1tan2(θ)

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