Prove: \(\displaystyle{\cot{{x}}}={\sin{{x}}}{\sin{{\left({\frac{{\pi}}{{{2}}}}-{x}\right)}}}+{{\cos}^{{2}}{x}}{\cot{{x}}}\)

Marzadri9lyy

Marzadri9lyy

Answered question

2022-03-28

Prove:
cotx=sinxsin(π2x)+cos2xcotx

Answer & Explanation

Riya Erickson

Riya Erickson

Beginner2022-03-29Added 12 answers

cotx=sinxsin(π2x)+cos2xcotx
=sinxsin(π2x)+cos2xcotx
=sinxcosx+cos2x(cosxsinx)
=sin2xcosx+cosx(cos2x)sinx
=cosx(sin2x+cos2x)sinx
=cosx(1)sinx
=1tanx
=cotx
Lana Hamilton

Lana Hamilton

Beginner2022-03-30Added 12 answers

RHS=sinxsin(π2x)+cos2xcotx
=sinxcosx+cos2xcotx
=cotx(sin2x+cos2x)
=cotx=LHS

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