Prove: \(\displaystyle{\frac{{{\tan{{x}}}}}{{{1}-{\cot{{x}}}}}}+{\frac{{{\cot{{x}}}}}{{{1}-{\tan{{x}}}}}}={\sec{{x}}}{\csc{{x}}}+{1}\)

amonitas3zeb

amonitas3zeb

Answered question

2022-03-29

Prove: tanx1cotx+cotx1tanx=secxcscx+1

Answer & Explanation

horieblersee275

horieblersee275

Beginner2022-03-30Added 17 answers

Since a3b3=(ab)(a2+ab+b2) and sin2x+cos2x=1, we obtain:
tanx1cotx+cotx1tanx=sin2xcosx(sinxcosx)cos2xsinx(sinxcosx)=
=sin3xcos3xsinxcosx(sinxcosx)=1+sinxcosxsinxcosx=secxcscx+1

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