Proving \(\displaystyle{\sin{{\left({\left({n}-\frac{{1}}{{2}}\right)}\phi\right)}}}+{\sin{{\left(\frac{\phi}{{2}}\right)}}}={\sin{{\left({\frac{{{n}+{1}}}{{{2}}}}\phi\right)}}}\)

jisu61hbke

jisu61hbke

Answered question

2022-03-28

Proving
sin((n12)ϕ)+sin(ϕ2)=sin(n+12ϕ)

Answer & Explanation

Kathleen Sanchez

Kathleen Sanchez

Beginner2022-03-29Added 7 answers

You need the prosthaphaeresis/sum-to-product formulae. Adding the expanded forms of sin(xy) and sin(x+y), you find
sin(xy)+sin(x+y)=2sinxcosy
and changing variables,
sinA+sinB=2sin12(A+B)cos12(AB)
Then the left-hand side of your identity is
sin(n12)ϕ+sin12ϕ=2sinn2ϕcosn+12ϕ
which is not often equal to what you have on the right...

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