Proving \(\displaystyle{\tan{{\left({\frac{{{a}+{b}}}{{{2}}}}\right)}}}={\frac{{{\sin{{a}}}+{\sin{{b}}}}}{{{\cos{{a}}}+{\cos{{b}}}}}}\)

Rex Maxwell

Rex Maxwell

Answered question

2022-03-30

Proving tan(a+b2)=sina+sinbcosa+cosb

Answer & Explanation

Gia Edwards

Gia Edwards

Beginner2022-03-31Added 12 answers

Use the formulas
sina+sinb=2sin(a+b2)cos(ab2)
cosa+cosb=2cos(a+b2)cos(ab2)
Therefore, we have
sina+sinbcosa+cosb=sin(a+b2)cos(a+b2)=tan(a+b2)

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