Proving Trig/Calc Identity \(\displaystyle{\frac{{{1}}}{{{1}-{\sin{{\left({x}\right)}}}}}}={\frac{{{1}+{\sin{{x}}}}}{{{\cos{{\left({x}\right)}}}^{{2}}}}}\)

resaplaha7dl

resaplaha7dl

Answered question

2022-03-30

Proving Trig/Calc Identity 11sin(x)=1+sinxcos(x)2

Answer & Explanation

Jayda Burch

Jayda Burch

Beginner2022-03-31Added 10 answers

You start from RHS =1+sin(x)cos2(x)=1+sin(x)1sin2(x)=1+sin(x)(1+sin(x))(1sin(x))=1(1sin(x))= LHS
Jesse Gates

Jesse Gates

Beginner2022-04-01Added 19 answers

11sinx=1+sinxcos2x
Working on the right side
1+sinxcos2x(1sinx1sinx)=1sin2xcos2x(1sinx)=cos2xcos2x(1sinx)=11sinx

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