\(\displaystyle{\tan{{\left({40}^{{\circ}}\right)}}}+{4}{\tan{{\left({10}^{{\circ}}\right)}}}={\cot{{\left({x}^{{\circ}}\right)}}}\) Find x My Try: we have \(\displaystyle{\tan{{x}}}-{\cot{{x}}}=-{2}{\cot{{2}}}{x}\) Subtracted

Sage Fry

Sage Fry

Answered question

2022-03-28

tan(40)+4tan(10)=cot(x) Find x
My Try:
we have tanxcotx=2cot2x
Subtracted both sides with cot(40) we get
tan40cot40+4tan10=cotxcot40
that is
2cot80+4tan10=cotxcot40

2tan10+cot40=cotx

Answer & Explanation

Janessa Foster

Janessa Foster

Beginner2022-03-29Added 12 answers

Just few steps needed after what you have done to complete
tan10+tan10+tan40=cotx
tan10+tan50(1tan40tan10)=cotx
tan10+tan50(tan50tan40)tan10=cotx
tan10+tan50tan10=cotx
tan50=cot40=cotx
if 0x90x=40

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?