How to solve the equation \(\displaystyle{{\tan}^{{2}}{\left({2}{x}\right)}}+{2}{\tan{{\left({2}{x}\right)}}}\cdot{\tan{{\left({3}{x}\right)}}}-{1}={0}\)

Zoie Phillips

Zoie Phillips

Answered question

2022-03-31

How to solve the equation
tan2(2x)+2tan(2x)tan(3x)1=0

Answer & Explanation

zevillageobau

zevillageobau

Beginner2022-04-01Added 13 answers

Using tan2B=2tanB1tan2B
tan3x=1tan22x2tan2x=1tan22x=cot4x=tan(π24x)
Now tany=tanAy=nπ+A where n is any integer

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