How would you evaluate the integral \(\displaystyle{\int_{{0}}^{{\pi}}}{\left({\frac{{\pi}}{{{2}}}}-{x}\right)}{\sin{{\left({\frac{{{3}{x}}}{{{2}}}}\right)}}}{\csc{{\left({\frac{{{x}}}{{{2}}}}\right)}}}{\left.{d}{x}\right.}\)

acidizihvzs

acidizihvzs

Answered question

2022-03-31

How would you evaluate the integral
0π(π2x)sin(3x2)csc(x2)dx

Answer & Explanation

membatas0v2v

membatas0v2v

Beginner2022-04-01Added 19 answers

Here are the steps
0π(π2x)sin(3x2)csc(x2)dx
=0π(π2x)(sin(3x2)sin(x2))dx
=0π(π2x)(3sin(x2)4sin3(x2)sin(x2))dx
=0π(π2x)(34sin2(x2))dx
=0π(π2x)(32(1cosx))dx
=0π(π2x)(1+2cosx)dx
=π20πdx+π0πcosxdx0πxdx20πxcosxdx
=π2[x]0π+π[sinx]0π[x22]0π2[xsinx+cosx]0π
=π22+πsinππ222(πsinπ+cosπ1)
=πsinπ2(πsinπ+cosπ1)
=02(011)=2(2)=4

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