I have the following trigonometric identity \(\displaystyle{\cos{{x}}}-{\frac{{{\cos{{x}}}}}{{{1}-{\tan{{x}}}}}}={\frac{{{\sin{{x}}}{\cos{{x}}}}}{{{\sin{{x}}}-{\cos{{x}}}}}}\)

Blackettyl2j

Blackettyl2j

Answered question

2022-03-29

I have the following trigonometric identity
cosxcosx1tanx=sinxcosxsinxcosx

Answer & Explanation

shvatismop1rj

shvatismop1rj

Beginner2022-03-30Added 10 answers

Observe that we need to eliminate tanx
So, using tanx=sinxcosx
cosxcosx1tanx
=cosx(111sinxcosx)
=cosx(1cosxcosxsinx)
=cosx(1+cosxsinxcosx)
=cosx(sinxsinxcosx)

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