I have to show that \(\displaystyle{\sin{{\left({\frac{{\pi}}{{{3}}}}\right)}}}={\frac{{{1}}}{{{2}}}}\sqrt{{{3}}}\)

palmantkf4u

palmantkf4u

Answered question

2022-03-31

I have to show that
sin(π3)=123

Answer & Explanation

Avery Maxwell

Avery Maxwell

Beginner2022-04-01Added 13 answers

So:
x=π3
3x=π
sin3x=sinπ
3sinx4sin3x=0
sinx=0  or  sinx=32  or  sinx=32
as  0<π3<π2, sinπ3=32

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