Proof of \(\displaystyle{\arctan{{2}}}=\frac{\pi}{{2}}-\frac{{\arctan{{1}}}}{{2}}\)

r1fa8dy5

r1fa8dy5

Answered question

2022-03-30

Proof of
arctan2=π2arctan12

Answer & Explanation

umgebautv6v2

umgebautv6v2

Beginner2022-03-31Added 10 answers

Note that
tan(π2x)=sin(π2x)cos(π2x)
But sin(π2x)=cos(x) and cos(π2x)=sin(x). So we have
tan(π2x)=cos(x)sin(x)=1tan(x)
So, if you take
tan(π2arctan(2))=1tan(arctan(2))=12
Since π2<π2arctan(2)<π2, this implies that
π2arctan(2)=arctan(12)
as claimed.

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