Proof of trig identity using t-formulae Show that \(\displaystyle{2}{\arctan{{x}}}={\arccos{{\frac{{{1}-{x}^{{2}}}}{{{1}+{x}^{{2}}}}}}}\) if

acidizihvzs

acidizihvzs

Answered question

2022-03-31

Proof of trig identity using t-formulae
Show that
2arctanx=arccos1x21+x2
if x>0, and
2arctanx=arccos1x21+x2
if x<0.
I have been able to equate the expressions by letting x=tan(y2), but I do not know how to show the different signs of the equation for x>0 and x<0.

Answer & Explanation

microsgopx6z7

microsgopx6z7

Beginner2022-04-01Added 14 answers

Calculation is most often the simplest course of action cos(2arctanx)
Set θ=arctanx and use the duplication formula:
cos2θ=1tan2θ1+tan2θ=1x21+x2
so   2arctanx±arccos1x21+x2mod2π
Now either 0θ<π2,so 02θ<π which is (strictly speaking, a part of) the range of arccos. In this instance, we determine that
2arctanx=arccos1x21+x2
or π2<θ<0, so π<2θ<0 likewise, we determine in this instance that
2arctanx=arccos1x21+x2

Jamie Maldonado

Jamie Maldonado

Beginner2022-04-02Added 10 answers

Let arctanx=yπ2<x<π2,tany=x
arccos1x21+x2=arccos(cos2y)={2y if 02yπ2y if π2y0 

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