Prove \(\displaystyle{\left[{\cos{{\left(\theta+{\frac{{\pi}}{{{3}}}}\right)}}}+{i}{\sin{{\left(\theta+{\frac{{\pi}}{{{3}}}}\right)}}}\right]}^{{6}}={\cos{{\left({6}\theta\right)}}}+{i}{\sin{{\left({6}\theta\right)}}}\)

aanvarendbq28

aanvarendbq28

Answered question

2022-03-31

Prove [cos(θ+π3)+isin(θ+π3)]6=cos(6θ)+isin(6θ)

Answer & Explanation

Endstufe5qa2

Endstufe5qa2

Beginner2022-04-01Added 7 answers

6(θ+π3)=6θ+2π
What's cos(α+2π)
Final hint: apply De Moivre to cos(a+b) and then solve.
Charlie Haley

Charlie Haley

Beginner2022-04-02Added 14 answers

(expi(θ+π3))6=expi(6θ+2π)=exp6iθ because exp2πi=1

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