Prove \(\displaystyle{\frac{{{\cos{{\left({x}\right)}}}}}{{{1}-{\tan{{\left({x}\right)}}}}}}+{\frac{{{\sin{{\left({x}\right)}}}}}{{{1}-{\cot{{\left({x}\right)}}}}}}={\sin{{\left({x}\right)}}}+{\cos{{\left({x}\right)}}}\)

Nadia Clayton

Nadia Clayton

Answered question

2022-03-31

Prove cos(x)1tan(x)+sin(x)1cot(x)=sin(x)+cos(x)

Answer & Explanation

anghoelv1lw

anghoelv1lw

Beginner2022-04-01Added 19 answers

Note that tan(x)=sin(x)cos(x)=1cot(x) and
cos(x)1-tan(x)+sin(x)1-cot(x)=cos2(x)cos(x)-sin(x)+sin2(x)sin(x)-cos(x)=sin2(x)-cos2(x)sin(x)-cos(x)

diocedss33

diocedss33

Beginner2022-04-02Added 12 answers

note that
cos(x)1tan(x)+sin(x)1cot(x)sin(x)cos(x)=cos(x)tan(x)cot(x)tan(x)sin(x)cot(x)+cos(x)tan(x)+sin(x)cot(x)
and note that
tan(x)cot(x)=1,cos(x)tan(x)=sin(x),sin(x)cot(x)=cos(x)

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