Prove \(\displaystyle{{\sec}^{{2}}{\frac{{\pi}}{{{7}}}}}+{{\sec}^{{2}}{\frac{{{2}\pi}}{{{7}}}}}+{{\sec}^{{2}}{\frac{{{3}\pi}}{{{7}}}}}={24}\) by using the roots of

jncuenodd4nf

jncuenodd4nf

Answered question

2022-04-01

Prove sec2π7+sec22π7+sec23π7=24 by using the roots of the polynomial x321x2+35x7=0

Answer & Explanation

Kailee Castro

Kailee Castro

Beginner2022-04-02Added 8 answers

let t=tan(θ) , we have
tan(7θ)=7t35t3+21t5t7121t2+35t47t6
Set tan(7θ)=0 then the polynomial
7t35t3+21t5t7=0
has roots t=0,tan(π7),,tan(6π7). So
x321x2+35x7=0
has roots x=tan2(π7),tan2(2π7),tan2(3π7). now let y=x+1

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