Prove that \(\displaystyle{\sin{{\left({12}^{\circ}\right)}}}{\sin{{\left({48}^{\circ}\right)}}}{\sin{{\left({54}^{\circ}\right)}}}={\frac{{{1}}}{{{8}}}}\)

Sage Fry

Sage Fry

Answered question

2022-03-31

Prove that
sin(12)sin(48)sin(54)=18

Answer & Explanation

Raiden Griffin

Raiden Griffin

Beginner2022-04-01Added 13 answers

Use the following:
sinθsin(π3θ)sin(π3+θ)=14sin(3θ)
Then you have:
sin(12)sin(6012)sin(60+12)=14sin(36)
sin(12)sin(48)=14sin(36)sin(72)
sin(12)sin(48)sin(54)=14sin(36)sin(72)sin(54)
=14sin(36)sin(72)cos(36)
sin(12)sin(48)sin(54)=18

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