Prove that \(\displaystyle{{\sin}^{{2}}\alpha}+{4}{{\sin}^{{4}}{\frac{{\alpha}}{{{2}}}}}={4}{{\sin}^{{2}}{\frac{{\alpha}}{{{2}}}}}\)

Lorelei Stanton

Lorelei Stanton

Answered question

2022-04-02

Prove that
sin2α+4sin4α2=4sin2α2

Answer & Explanation

haiguetenteme7zyu

haiguetenteme7zyu

Beginner2022-04-03Added 13 answers

sin2α+4sin4α2
=(2sinα2cosα2)2+4sin4α2
=4sin2α2cos2α2+4sin4α2
=4sin2α2(cos2α2+sin2α2)
=4sin2α21
=4sin2α2
same way second part can be prove

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