Prove that \(\displaystyle{\text{cosh}{{\left({x}\right)}}}={\sec{{\left(\theta\right)}}}\) if \(\displaystyle{x}={\ln{{\left({\sec{\theta}}+{\tan{\theta}}\right)}}}\)

tibukooinm

tibukooinm

Answered question

2022-03-31

Prove that cosh(x)=sec(θ) if x=ln(secθ+tanθ)

Answer & Explanation

Matronola3zw6

Matronola3zw6

Beginner2022-04-01Added 10 answers

You got to
coshx=12(secθ+tanθ+1secθ+tanθ)
Write this is as single fraction:
12(secθ+tanθ+1secθ+tanθ)=(secθ+tanθ)2+12(secθ+tanθ)
Expand and remember that 1+tan2θ=sec2θ
(secθ+tanθ)2+12(secθ+tanθ)=sec2θ+2tanθsecθ+tan2θ+12(secθ+tanθ)
=2sec2θ+2secθtanθ2(secθ+tanθ)
=(2secθ)(secθ+tanθ)2(secθ+tanθ)=secθ

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