Prove that \(\displaystyle{\frac{{{1}+{\sin{\theta}}+{i}{\cos{\theta}}}}{{{1}+{\sin{\theta}}-{i}{\cos{\theta}}}}}={\sin{\theta}}+{i}{\cos{\theta}}\)

annlanw09y

annlanw09y

Answered question

2022-04-02

Prove that 1+sinθ+icosθ1+sinθicosθ=sinθ+icosθ

Answer & Explanation

Janessa Foster

Janessa Foster

Beginner2022-04-03Added 12 answers

This is just a matter of observing that
(1+sinθicosθ)(sinθ+icosθ)=sinθ+sin2θ+cos2θ+i(cosθ+sinθcosθcosθsinθ)
=1+sinθ+icosθ
Makenzie Hart

Makenzie Hart

Beginner2022-04-04Added 8 answers

(ej0+ejθ)ejθ=1+ejθ
Much simpler would be to convert to polar coordinates.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?